{"title":"Probability Codebreakers","description":"\u003cdiv\u003e\n\u003cp\u003e\u003cstrong\u003eBrowse topics\u003c\/strong\u003e\u003c\/p\u003e\n\u003cp\u003e\u003ca href=\"\/collections\/probability-codebreakers\"\u003eAll resources\u003c\/a\u003e  ·  \u003ca href=\"\/collections\/events-and-probability-codebreakers\"\u003eEvents and probability\u003c\/a\u003e  ·  \u003ca href=\"\/collections\/relative-and-expected-frequency-codebreakers\"\u003eRelative and expected frequency\u003c\/a\u003e  ·  \u003ca href=\"\/collections\/systematic-counting-codebreakers\"\u003eSystematic counting\u003c\/a\u003e\u003c\/p\u003e\n\u003c\/div\u003e\u003cdiv\u003e\n\u003cp\u003e\u003cstrong\u003eBack to resource range\u003c\/strong\u003e\u003c\/p\u003e\n\u003cp\u003e\u003ca href=\"\/collections\/codebreakers\"\u003eCodebreakers\u003c\/a\u003e\u003c\/p\u003e\n\u003c\/div\u003e","products":[{"product_id":"free-probability-fundamentals-maths-codebreaker-answers-included","title":"FREE Probability Fundamentals | Maths Codebreaker | Answers Included","description":"\u003cp\u003eFREE DOWNLOAD - no purchase required.\u003c\/p\u003e\u003cp\u003eCalculate simple probabilities, complements and mutually exclusive event totals.\u003c\/p\u003e\u003cp\u003eThis FREE resource contains one complete A4 pupil worksheet with 22 questions and a matching answer page with workings, plus a product-family guide. Pupils solve the maths, match answers to letters in the code grid and decode the hidden words.\u003c\/p\u003e\u003cp\u003eDifficulty: Level 3 of 10 within this range (1 is easiest; 10 is most demanding). These levels are a guide to relative challenge, not GCSE grades.\u003c\/p\u003e\u003cp\u003eThree questions from this worksheet:\u003cbr\u003e1. A bag contains 5 red and 19 blue counters. One counter is chosen at random. Find the probability that it is red.\u003cbr\u003e2. A fair spinner has 20 equal sections, of which 4 are shaded. Find the probability that it lands on a shaded section.\u003cbr\u003e3. 15 of 30 cards are marked. One card is chosen at random. Find the probability of choosing an unmarked card.\u003c\/p\u003e\u003cp\u003eUse for focused practice, consolidation, homework or a lesson activity after teaching the method. Print the pupil page for learners and retain the answer page for checking. Follow the rounding and unit instructions on the sheet.\u003c\/p\u003e\u003cp\u003eThis resource belongs to a completed 100-topic Maths Codebreakers range. Halloween codebreaker resources are also available. A mixed-topic revision codebreaker range is coming soon. These other ranges are separate resources and are not included in this download.\u003c\/p\u003e","brand":"Beyond Printables","offers":[{"title":"Default Title","offer_id":57558381887863,"sku":"BP-CB-032","price":0.0,"currency_code":"GBP","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0942\/4414\/3479\/files\/Probability_Fundamentals_Maths_Codebreaker_Thumbnail_1.png?v=1792003873"},{"product_id":"free-relative-frequency-and-expected-frequency-maths-codebreaker-answers-included","title":"FREE Relative Frequency and Expected Frequency | Maths Codebreaker | Answers Included","description":"\u003cp\u003eFREE DOWNLOAD - no purchase required.\u003c\/p\u003e\u003cp\u003eCalculate relative frequencies, expected counts and scaled predictions.\u003c\/p\u003e\u003cp\u003eThis FREE resource contains one complete A4 pupil worksheet with 22 questions and a matching answer page with workings, plus a product-family guide. Pupils solve the maths, match answers to letters in the code grid and decode the hidden words.\u003c\/p\u003e\u003cp\u003eDifficulty: Level 5 of 10 within this range (1 is easiest; 10 is most demanding). These levels are a guide to relative challenge, not GCSE grades.\u003c\/p\u003e\u003cp\u003eThree questions from this worksheet:\u003cbr\u003e1. The probability of success in each trial is 1\/3. In 42 trials, find the expected number of successes.\u003cbr\u003e2. 30 successes occur in 600 trials. Find the relative frequency as a percentage.\u003cbr\u003e3. The probability of success in each trial is 0.5; the expected number of successes is 13.5. Find the number of trials.\u003c\/p\u003e\u003cp\u003eUse for focused practice, consolidation, homework or a lesson activity after teaching the method. Print the pupil page for learners and retain the answer page for checking. Follow the rounding and unit instructions on the sheet.\u003c\/p\u003e\u003cp\u003eThis resource belongs to a completed 100-topic Maths Codebreakers range. Halloween codebreaker resources are also available. A mixed-topic revision codebreaker range is coming soon. These other ranges are separate resources and are not included in this download.\u003c\/p\u003e","brand":"Beyond Printables","offers":[{"title":"Default Title","offer_id":57558393192823,"sku":"BP-CB-038","price":0.0,"currency_code":"GBP","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0942\/4414\/3479\/files\/Relative_Frequency_and_Expected_Frequency_Maths_Codebreaker_Thumbnail_1.png?v=1792004039"},{"product_id":"free-systematic-counting-and-the-product-rule-maths-codebreaker-answers-included","title":"FREE Systematic Counting and the Product Rule | Maths Codebreaker | Answers Included","description":"\u003cp\u003eFREE DOWNLOAD - no purchase required.\u003c\/p\u003e\u003cp\u003eCount outcomes using addition and product rules, including ordered choices without repetition.\u003c\/p\u003e\u003cp\u003eThis FREE resource contains one complete A4 pupil worksheet with 21 questions and a matching answer page with workings, plus a product-family guide. Pupils solve the maths, match answers to letters in the code grid and decode the hidden words.\u003c\/p\u003e\u003cp\u003eDifficulty: Level 5 of 10 within this range (1 is easiest; 10 is most demanding). These levels are a guide to relative challenge, not GCSE grades.\u003c\/p\u003e\u003cp\u003eThree questions from this worksheet:\u003cbr\u003e1. A menu has 8 starters and 7 main courses. A meal consists of one starter and one main course. How many different meals can be chosen?\u003cbr\u003e2. There are 4 roads from A to B and 7 roads from B to C. A journey goes from A to C via B. How many different routes can be taken?\u003cbr\u003e3. A shop sells 6 different shirts. Choosing one shirt and one pair of trousers gives 48 different outfits. How many different pairs of trousers does the shop sell?\u003c\/p\u003e\u003cp\u003eUse for focused practice, consolidation, homework or a lesson activity after teaching the method. Print the pupil page for learners and retain the answer page for checking. Follow the rounding and unit instructions on the sheet.\u003c\/p\u003e\u003cp\u003eThis resource belongs to a completed 100-topic Maths Codebreakers range. Halloween codebreaker resources are also available. A mixed-topic revision codebreaker range is coming soon. These other ranges are separate resources and are not included in this download.\u003c\/p\u003e","brand":"Beyond Printables","offers":[{"title":"Default Title","offer_id":57558409347447,"sku":"BP-CB-045","price":0.0,"currency_code":"GBP","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0942\/4414\/3479\/files\/Systematic_Counting_and_the_Product_Rule_Maths_Codebreaker_Thumbnail_1.png?v=1792004231"},{"product_id":"premium-combined-independent-events-maths-codebreaker-answers-included","title":"Premium Combined Independent Events | Maths Codebreaker | Answers Included","description":"\u003cp\u003ePREMIUM RESOURCE - available to purchase; this is not a free download.\u003c\/p\u003e\u003cp\u003eCombine independent events, including at least one, neither and complements.\u003c\/p\u003e\u003cp\u003eThis Premium paid resource contains one complete A4 pupil worksheet with 21 questions and a matching answer page with workings, plus a product-family guide. Pupils solve the maths, match answers to letters in the code grid and decode the hidden words.\u003c\/p\u003e\u003cp\u003eDifficulty: Level 7 of 10 within this range (1 is easiest; 10 is most demanding). These levels are a guide to relative challenge, not GCSE grades.\u003c\/p\u003e\u003cp\u003eThree questions from this worksheet:\u003cbr\u003e1. P(heads) = 4\/5; P(red) = 3\/4. Find P(tails and a non-red result)\u003cbr\u003e2. P(heads) = 1\/5; P(red) = 1\/4. Find P(heads or red, or both)\u003cbr\u003e3. P(heads) = 4\/5; P(red) = 3\/4. Find P(heads and red)\u003c\/p\u003e\u003cp\u003eUse for focused practice, consolidation, homework or a lesson activity after teaching the method. Print the pupil page for learners and retain the answer page for checking. Follow the rounding and unit instructions on the sheet.\u003c\/p\u003e\u003cp\u003eThis resource belongs to a completed 100-topic Maths Codebreakers range. Halloween codebreaker resources are also available. A mixed-topic revision codebreaker range is coming soon. These other ranges are separate resources and are not included in this download.\u003c\/p\u003e","brand":"Beyond Printables","offers":[{"title":"Default Title","offer_id":57558418719095,"sku":"BP-CB-053","price":1.0,"currency_code":"GBP","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0942\/4414\/3479\/files\/Combined_Independent_Events_Maths_Codebreaker_Thumbnail_1.png?v=1792004446"},{"product_id":"premium-probability-without-replacement-maths-codebreaker-answers-included","title":"Premium Probability Without Replacement | Maths Codebreaker | Answers Included","description":"\u003cp\u003ePREMIUM RESOURCE - available to purchase; this is not a free download.\u003c\/p\u003e\u003cp\u003eCalculate two-event probabilities without replacement, including at least one outcomes.\u003c\/p\u003e\u003cp\u003eThis Premium paid resource contains one complete A4 pupil worksheet with 20 questions and a matching answer page with workings, plus a product-family guide. Pupils solve the maths, match answers to letters in the code grid and decode the hidden words.\u003c\/p\u003e\u003cp\u003eDifficulty: Level 8 of 10 within this range (1 is easiest; 10 is most demanding). These levels are a guide to relative challenge, not GCSE grades.\u003c\/p\u003e\u003cp\u003eThree questions from this worksheet:\u003cbr\u003e1. A bag has 3 red and 2 blue counters. Find the probability of choosing two blue counters in two draws without replacement.\u003cbr\u003e2. Remove one blue counter from 2 red and 8 blue counters. Find the probability that the next randomly chosen counter is red.\u003cbr\u003e3. A bag has 6 red and 2 blue counters. Find the probability of choosing two red counters in two draws without replacement.\u003c\/p\u003e\u003cp\u003eUse for focused practice, consolidation, homework or a lesson activity after teaching the method. Print the pupil page for learners and retain the answer page for checking. Follow the rounding and unit instructions on the sheet.\u003c\/p\u003e\u003cp\u003eThis resource belongs to a completed 100-topic Maths Codebreakers range. Halloween codebreaker resources are also available. A mixed-topic revision codebreaker range is coming soon. These other ranges are separate resources and are not included in this download.\u003c\/p\u003e","brand":"Beyond Printables","offers":[{"title":"Default Title","offer_id":57558432842103,"sku":"BP-CB-073","price":1.0,"currency_code":"GBP","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0942\/4414\/3479\/files\/Probability_Without_Replacement_Maths_Codebreaker_Thumbnail_1.png?v=1792005011"}],"url":"https:\/\/beyondprintables.com\/collections\/probability-codebreakers.oembed","provider":"Beyond Printables","version":"1.0","type":"link"}